3.1.21 \(\int e^{c (a+b x)} \tan (d+e x) \, dx\) [21]

Optimal. Leaf size=78 \[ -\frac {i e^{c (a+b x)}}{b c}+\frac {2 i e^{c (a+b x)} \, _2F_1\left (1,-\frac {i b c}{2 e};1-\frac {i b c}{2 e};-e^{2 i (d+e x)}\right )}{b c} \]

[Out]

-I*exp(c*(b*x+a))/b/c+2*I*exp(c*(b*x+a))*hypergeom([1, -1/2*I*b*c/e],[1-1/2*I*b*c/e],-exp(2*I*(e*x+d)))/b/c

________________________________________________________________________________________

Rubi [A]
time = 0.05, antiderivative size = 78, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {4527, 2225, 2283} \begin {gather*} \frac {2 i e^{c (a+b x)} \, _2F_1\left (1,-\frac {i b c}{2 e};1-\frac {i b c}{2 e};-e^{2 i (d+e x)}\right )}{b c}-\frac {i e^{c (a+b x)}}{b c} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[E^(c*(a + b*x))*Tan[d + e*x],x]

[Out]

((-I)*E^(c*(a + b*x)))/(b*c) + ((2*I)*E^(c*(a + b*x))*Hypergeometric2F1[1, ((-1/2*I)*b*c)/e, 1 - ((I/2)*b*c)/e
, -E^((2*I)*(d + e*x))])/(b*c)

Rule 2225

Int[((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.), x_Symbol] :> Simp[(F^(c*(a + b*x)))^n/(b*c*n*Log[F]), x] /; Fre
eQ[{F, a, b, c, n}, x]

Rule 2283

Int[((a_) + (b_.)*(F_)^((e_.)*((c_.) + (d_.)*(x_))))^(p_)*(G_)^((h_.)*((f_.) + (g_.)*(x_))), x_Symbol] :> Simp
[a^p*(G^(h*(f + g*x))/(g*h*Log[G]))*Hypergeometric2F1[-p, g*h*(Log[G]/(d*e*Log[F])), g*h*(Log[G]/(d*e*Log[F]))
+ 1, Simplify[(-b/a)*F^(e*(c + d*x))]], x] /; FreeQ[{F, G, a, b, c, d, e, f, g, h, p}, x] && (ILtQ[p, 0] || G
tQ[a, 0])

Rule 4527

Int[(F_)^((c_.)*((a_.) + (b_.)*(x_)))*Tan[(d_.) + (e_.)*(x_)]^(n_.), x_Symbol] :> Dist[I^n, Int[ExpandIntegran
d[F^(c*(a + b*x))*((1 - E^(2*I*(d + e*x)))^n/(1 + E^(2*I*(d + e*x)))^n), x], x], x] /; FreeQ[{F, a, b, c, d, e
}, x] && IntegerQ[n]

Rubi steps

\begin {align*} \int e^{c (a+b x)} \tan (d+e x) \, dx &=i \int \left (-e^{c (a+b x)}+\frac {2 e^{c (a+b x)}}{1+e^{2 i (d+e x)}}\right ) \, dx\\ &=-\left (i \int e^{c (a+b x)} \, dx\right )+2 i \int \frac {e^{c (a+b x)}}{1+e^{2 i (d+e x)}} \, dx\\ &=-\frac {i e^{c (a+b x)}}{b c}+\frac {2 i e^{c (a+b x)} \, _2F_1\left (1,-\frac {i b c}{2 e};1-\frac {i b c}{2 e};-e^{2 i (d+e x)}\right )}{b c}\\ \end {align*}

________________________________________________________________________________________

Mathematica [B] Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(166\) vs. \(2(78)=156\).
time = 0.46, size = 166, normalized size = 2.13 \begin {gather*} \frac {e^{c (a+b x)} \left (2 b c e^{2 i (d+e x)} \, _2F_1\left (1,1-\frac {i b c}{2 e};2-\frac {i b c}{2 e};-e^{2 i (d+e x)}\right )-(b c+2 i e) \left (1-e^{2 i d}+2 e^{2 i d} \, _2F_1\left (1,-\frac {i b c}{2 e};1-\frac {i b c}{2 e};-e^{2 i (d+e x)}\right )\right )\right )}{b c (i b c-2 e) \left (1+e^{2 i d}\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[E^(c*(a + b*x))*Tan[d + e*x],x]

[Out]

(E^(c*(a + b*x))*(2*b*c*E^((2*I)*(d + e*x))*Hypergeometric2F1[1, 1 - ((I/2)*b*c)/e, 2 - ((I/2)*b*c)/e, -E^((2*
I)*(d + e*x))] - (b*c + (2*I)*e)*(1 - E^((2*I)*d) + 2*E^((2*I)*d)*Hypergeometric2F1[1, ((-1/2*I)*b*c)/e, 1 - (
(I/2)*b*c)/e, -E^((2*I)*(d + e*x))])))/(b*c*(I*b*c - 2*e)*(1 + E^((2*I)*d)))

________________________________________________________________________________________

Maple [F]
time = 0.03, size = 0, normalized size = 0.00 \[\int {\mathrm e}^{c \left (b x +a \right )} \tan \left (e x +d \right )\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(c*(b*x+a))*tan(e*x+d),x)

[Out]

int(exp(c*(b*x+a))*tan(e*x+d),x)

________________________________________________________________________________________

Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(c*(b*x+a))*tan(e*x+d),x, algorithm="maxima")

[Out]

2*(b*c*e^(b*c*x + a*c)*sin(2*x*e + 2*d) - 2*cos(2*x*e + 2*d)*e^(b*c*x + a*c + 1) + 2*(b^2*c^2 + (b^2*c^2 + 4*e
^2)*cos(2*x*e + 2*d)^2 + (b^2*c^2 + 4*e^2)*sin(2*x*e + 2*d)^2 + 2*(b^2*c^2 + 4*e^2)*cos(2*x*e + 2*d) + 4*e^2)*
integrate((b*c*cos(4*x*e + 4*d)*e^(b*c*x + a*c + 1) + 2*b*c*cos(2*x*e + 2*d)*e^(b*c*x + a*c + 1) + b*c*e^(b*c*
x + a*c + 1) + 2*e^(b*c*x + a*c + 2)*sin(4*x*e + 4*d) + 4*e^(b*c*x + a*c + 2)*sin(2*x*e + 2*d))/(b^2*c^2 + (b^
2*c^2 + 4*e^2)*cos(4*x*e + 4*d)^2 + 4*(b^2*c^2 + 4*e^2)*cos(2*x*e + 2*d)^2 + (b^2*c^2 + 4*e^2)*sin(4*x*e + 4*d
)^2 + 4*(b^2*c^2 + 4*e^2)*sin(4*x*e + 4*d)*sin(2*x*e + 2*d) + 4*(b^2*c^2 + 4*e^2)*sin(2*x*e + 2*d)^2 + 2*(b^2*
c^2 + 2*(b^2*c^2 + 4*e^2)*cos(2*x*e + 2*d) + 4*e^2)*cos(4*x*e + 4*d) + 4*(b^2*c^2 + 4*e^2)*cos(2*x*e + 2*d) +
4*e^2), x) - 2*e^(b*c*x + a*c + 1))/(b^2*c^2 + (b^2*c^2 + 4*e^2)*cos(2*x*e + 2*d)^2 + (b^2*c^2 + 4*e^2)*sin(2*
x*e + 2*d)^2 + 2*(b^2*c^2 + 4*e^2)*cos(2*x*e + 2*d) + 4*e^2)

________________________________________________________________________________________

Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(c*(b*x+a))*tan(e*x+d),x, algorithm="fricas")

[Out]

integral(e^(b*c*x + a*c)*tan(x*e + d), x)

________________________________________________________________________________________

Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} e^{a c} \int e^{b c x} \tan {\left (d + e x \right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(c*(b*x+a))*tan(e*x+d),x)

[Out]

exp(a*c)*Integral(exp(b*c*x)*tan(d + e*x), x)

________________________________________________________________________________________

Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(c*(b*x+a))*tan(e*x+d),x, algorithm="giac")

[Out]

integrate(e^((b*x + a)*c)*tan(e*x + d), x)

________________________________________________________________________________________

Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int {\mathrm {e}}^{c\,\left (a+b\,x\right )}\,\mathrm {tan}\left (d+e\,x\right ) \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(c*(a + b*x))*tan(d + e*x),x)

[Out]

int(exp(c*(a + b*x))*tan(d + e*x), x)

________________________________________________________________________________________